-0.7x^2+0.5=0

Solution for -0.7x^2+0.5=0 equation:

-0.7x^2+0.5=0

a = -0.7; b = 0; c = +0.5;
Δ = b2-4ac
Δ = 02-4·(-0.7)·0.5
Δ = 1.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.4}}{2*-0.7}=\frac{0-\sqrt{1.4}}{-1.4}
=-\frac{\sqrt{}}{-1.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.4}}{2*-0.7}=\frac{0+\sqrt{1.4}}{-1.4}
=\frac{\sqrt{}}{-1.4}
$